9 May
2002
9 May
'02
12:36 a.m.
On Wed, 8 May 2002 20:21:18 -0400, "Kev" <KKlopp@erols.com> wrote:
Okay, a checksum on a single byte of FF yeilds an FF
I found this to be interesting......
Byte 0 = F3 Sig = FE Byte 1 = 3E Sig = 1EE8 Byte 2 = 00 Sig = 1EE8 Byte 3 = ED Sig = 225A Byte 4 = 47 Sig = 56B6
It isn't using the last read byte as the divisor is it?
Or are you saying: F3 = FE F3 3E = 1EE8 F3 3E 00 = 1EE8 (Your right, this is interesting) So not all values equal themselves? F3 = FE? -Zonn